p^2+10p-20=4

Solution for p^2+10p-20=4 equation:

Simplifying
p2 + 10p + -20 = 4

Reorder the terms:
-20 + 10p + p2 = 4

Solving
-20 + 10p + p2 = 4

Solving for variable 'p'.

Reorder the terms:
-20 + -4 + 10p + p2 = 4 + -4

Combine like terms: -20 + -4 = -24
-24 + 10p + p2 = 4 + -4

Combine like terms: 4 + -4 = 0
-24 + 10p + p2 = 0

Factor a trinomial.
(-12 + -1p)(2 + -1p) = 0

Subproblem 1
Set the factor '(-12 + -1p)' equal to zero and attempt to solve:

Simplifying
-12 + -1p = 0

Solving
-12 + -1p = 0

Move all terms containing p to the left, all other terms to the right.

Add '12' to each side of the equation.
-12 + 12 + -1p = 0 + 12

Combine like terms: -12 + 12 = 0
0 + -1p = 0 + 12
-1p = 0 + 12

Combine like terms: 0 + 12 = 12
-1p = 12

Divide each side by '-1'.
p = -12

Simplifying
p = -12
Subproblem 2
Set the factor '(2 + -1p)' equal to zero and attempt to solve:

Simplifying
2 + -1p = 0

Solving
2 + -1p = 0

Move all terms containing p to the left, all other terms to the right.

Add '-2' to each side of the equation.
2 + -2 + -1p = 0 + -2

Combine like terms: 2 + -2 = 0
0 + -1p = 0 + -2
-1p = 0 + -2

Combine like terms: 0 + -2 = -2
-1p = -2

Divide each side by '-1'.
p = 2

Simplifying
p = 2
Solution
p = {-12, 2}